* [unittest] add comment for getleftafterdeleteworkhour.
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Regular → Executable
+25
-3
@@ -9,7 +9,6 @@ $task->estimate->range('2,2');
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$task->consumed->range('1,2');
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$task->left->range('1,0');
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$task->status->range('doing,done');
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$task->gen(2);
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@@ -22,13 +21,36 @@ $effort->deleted->range('0');
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$effort->gen(3);
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/**
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title=获取删除工时后的剩余工时
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timeout=0
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cid=1
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*/
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- 删除ID为1的工时
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- 属性taskEstimate @2
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- 属性taskConsumed @1
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- 属性taskLeft @1
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- 属性effortConsumed @1
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- 属性effortLeft @1
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- 属性left @1
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- 删除ID为2的工时
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- 属性taskEstimate @2
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- 属性taskConsumed @2
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- 属性taskLeft @0
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- 属性effortConsumed @1
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- 属性effortLeft @1
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- 属性left @0
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- 删除ID为3的工时
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- 属性taskEstimate @2
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- 属性taskConsumed @2
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- 属性taskLeft @0
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- 属性effortConsumed @1
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- 属性effortLeft @0
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- 属性left @1
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*/
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$task = new taskTest();
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r($task->getLeftAfterDeleteWorkhourTest(1)) && p('taskEstimate,taskConsumed,taskLeft,effortConsumed,effortLeft,left') && e('2,1,1,1,1,1'); // 删除ID为1的工时
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r($task->getLeftAfterDeleteWorkhourTest(2)) && p('taskEstimate,taskConsumed,taskLeft,effortConsumed,effortLeft,left') && e('2,2,0,1,1,0'); // 删除ID为2的工时
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r($task->getLeftAfterDeleteWorkhourTest(3)) && p('taskEstimate,taskConsumed,taskLeft,effortConsumed,effortLeft,left') && e('2,2,0,1,0,1'); // 删除ID为3的工时
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r($task->getLeftAfterDeleteWorkhourTest(3)) && p('taskEstimate,taskConsumed,taskLeft,effortConsumed,effortLeft,left') && e('2,2,0,1,0,1'); // 删除ID为3的工时
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