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James Newton-King
2012-07-31 20:48:27 +12:00
parent 2deaac6a0a
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Doc/LINQtoJSON.aml
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<para>There are a number of different options when it comes to creating
JSON using LINQ to JSON.</para>
<para>The first to create objects imperatively. You
<para>The first option is to set values one at a time. You
have total control but it is more verbose than other options.</para>
<code lang="cs" source="..\Src\Newtonsoft.Json.Tests\Documentation\LinqToJsonTests.cs" region="LinqToJsonCreateNormal" title="Creating JSON" />
<para>Another option is to create JSON objects declaratively.</para>
<para>Another option is to create JSON objects declaratively using LINQ.</para>
<code lang="cs" source="..\Src\Newtonsoft.Json.Tests\Documentation\LinqToJsonTests.cs" region="LinqToJsonCreateDeclaratively" title="Creating JSON Declaratively" />
<para>Finally you can create a JSON object from a non-JSON type using the
<codeEntityReference>Overload:Newtonsoft.Json.Linq.JObject.FromObject</codeEntityReference>
method. The example below is creating a JSON object from an anonymous object but any
.NET type can be used with FromObject.</para>
.NET type can be used with FromObject to create JSON.</para>
<code lang="cs" source="..\Src\Newtonsoft.Json.Tests\Documentation\LinqToJsonTests.cs" region="LinqToJsonCreateFromObject" title="Creating JSON from an Object" />
</content>