liugangandClaude
2a288e9e1e
🤖 Generated with [Claude Code](https://claude.ai/code) Co-Authored-By: Claude <noreply@anthropic.com>
65 lines
2.8 KiB
PHP
Executable File
65 lines
2.8 KiB
PHP
Executable File
#!/usr/bin/env php
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<?php
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/**
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title=测试 docZen::getDocChildrenByRecursion();
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timeout=0
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cid=0
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- 步骤1：层级为0时边界情况 @0
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- 步骤2：层级为负数时边界情况 @0
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- 步骤3：层级为1时获取直接子文档 @3
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- 步骤4：层级为2时获取多级子文档 @3
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- 步骤5：没有子文档的情况 @0
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*/
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// 1. 导入依赖（路径固定，不可修改）
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include dirname(__FILE__, 5) . '/test/lib/init.php';
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include dirname(__FILE__, 2) . '/lib/doc.unittest.class.php';
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// 2. zendata数据准备（根据需要配置）
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$table = zenData('doc');
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$table->id->range('1-20');
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$table->product->range('1-20');
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$table->project->range('0{20}');
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$table->execution->range('0{20}');
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$table->lib->range('1{20}');
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$table->template->range('{20}');
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$table->templateType->range('{20}');
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$table->chapterType->range('article{20}');
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$table->module->range('0{20}');
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$table->title->range('文档1,文档2,文档3,文档4,文档5,子文档1,子文档2,子文档3,孙文档1,孙文档2,孙文档3,曾孙文档1,曾孙文档2,曾孙文档3,叶子文档1,叶子文档2,叶子文档3,叶子文档4,叶子文档5,叶子文档6');
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$table->keywords->range('关键词1,关键词2,关键词3,关键词4,关键词5,关键词6,关键词7,关键词8,关键词9,关键词10,关键词11,关键词12,关键词13,关键词14,关键词15,关键词16,关键词17,关键词18,关键词19,关键词20');
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$table->type->range('text{20}');
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$table->parent->range('0,0,0,0,0,1,1,1,2,2,2,3,3,3,10,10,10,11,11,11');
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$table->path->range('0{20}');
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$table->grade->range('0{20}');
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$table->order->range('0{20}');
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$table->views->range('0{20}');
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$table->addedBy->range('admin{20}');
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$table->addedDate->range(date('Y-m-d H:i:s'));
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$table->editedBy->range('admin{20}');
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$table->editedDate->range(date('Y-m-d H:i:s'));
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$table->acl->range('open{20}');
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$table->groups->range('{20}');
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$table->users->range('{20}');
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$table->draft->range('{20}');
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$table->version->range('1{20}');
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$table->deleted->range('0{20}');
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$table->status->range('normal{20}');
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$table->gen(20);
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// 3. 用户登录（选择合适角色）
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su('admin');
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// 4. 创建测试实例（变量名与模块名一致）
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$docTest = new docTest();
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// 5. 🔴 强制要求：必须包含至少5个测试步骤
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r(count($docTest->getDocChildrenByRecursionTest(1, 0))) && p() && e('0'); // 步骤1：层级为0时边界情况
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r(count($docTest->getDocChildrenByRecursionTest(1, -1))) && p() && e('0'); // 步骤2：层级为负数时边界情况
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r(count($docTest->getDocChildrenByRecursionTest(1, 1))) && p() && e('3'); // 步骤3：层级为1时获取直接子文档
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r(count($docTest->getDocChildrenByRecursionTest(1, 2))) && p() && e('3'); // 步骤4：层级为2时获取多级子文档
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r(count($docTest->getDocChildrenByRecursionTest(15, 1))) && p() && e('0'); // 步骤5：没有子文档的情况
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